The amount of poop produced on the GRE is directly proportional to the difficulty of the questions, and inversely proportional to the time provided for the test and the degree of consciousness of the test taker.
If P is the amount of poop produced, D is the difficulty of the questions, t is the time allowed for the test and d is the degree of consciousness of the test taker, then by the above statement
P α D
and
P α 1/dt
Combining the above we get
P α D/dt
or
P = AD/dt
where
A is the absurdity co-efficient of the English Language section. The higher the value of A, the more the poop!
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